Seongbeom Park e8f69a8743 Count cycles by iteration
Verifying solution...
Test 1 passed!
Test 2 passed!
Test 3 failed  [Hidden]
Test 4 passed! [Hidden]
Test 5 failed  [Hidden]
Test 6 failed  [Hidden]
Test 7 failed  [Hidden]
Test 8 failed  [Hidden]
Test 9 passed! [Hidden]
Test 10 failed  [Hidden]
2022-03-21 05:35:25 +09:00

52 lines
1.3 KiB
Python

import math
import numpy as np
def solution(w, h, s):
return str(sum([s**cycle for cycle in generate_cycles(w, h)])/(math.factorial(w)*math.factorial(h)))
def generate_cycles(w, h):
identity = np.arange(w*h).reshape((w, h))
for i in generate_permutation(list(range(w))):
for j in generate_permutation(list(range(h))):
yield count_cycle(identity[i][:, j])
def generate_permutation(numbers):
if len(numbers) == 1:
yield numbers
else:
for i, n in enumerate(numbers):
for j in generate_permutation(numbers[:i] + numbers[i+1:]):
yield [n] + j
def count_cycle(arr):
cycle = np.zeros(arr.shape, dtype=int)
w, h = arr.shape
cycle_id = 0
for i in range(w):
for j in range(h):
x, y = i, j
if cycle[x, y] == 0:
cycle_id += 1
while cycle[x, y] == 0:
cycle[x, y] = cycle_id
x, y = arr[x, y]/h, arr[x, y]%h
return cycle_id
tests = [
([2, 3, 4], '430'),
([2, 2, 2], '7'),
([1, 1, 2], '2'),
([1, 1, 3], '3'),
([2, 1, 2], '3'),
([1, 2, 2], '3'),
([3, 1, 2], '4'),
([1, 3, 2], '4'),
([2, 3, 2], '13'),
]
for i, o in tests:
result = solution(*i)
print (i, result == o, result, o)